5y^2/3+19y^1/3+12=0

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Solution for 5y^2/3+19y^1/3+12=0 equation: 


y in (-oo:+oo)

(5*y^2)/3+(19*y^1)/3+12 = 0

(5*y^2)/3+(19*y)/3+12 = 0

5/3*y^2+19/3*y+12 = 0

DELTA = (19/3)^2-(5/3*4*12)

DELTA = -359/9

DELTA < 0

y belongs to the empty set

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